light fixtures = 710 watts

receptacles = 1,980 watts

g. door opener = 720 watts

window a/c = 1,350 watts

gross sum total = 4,760 watts

(sum total X

**1.25***)/240 = 24.8 amps

*any word on whether this portion is actually needed?

So with or without the 1.25 adjustment along with a "worst case" scenario of running a/c and constantly opening/closing the door looks like I'm good with the 30 amp subpanel currently in place.

Now, back to how the square footage math is supposed to fit for the remainder. Due to how and where it's installed the main panel only houses 2 subpanel feeds and the general lighting and house receptacle circuits (2). I think it might make sense to split the single house receptacle circuit at some point which would bring me to 3 circuits aside from the sub feeds. The house subpanel located in the dining room accomodates the 2 required appliance circuits, 1 laundry circuit, the 1 bathroom circuit as well as assorted dedicated circuits for a total of 12 circuits. When figuring the square footage math do I omit the areas served by the house subpanel and just include the living and bedroom areas? Finally, when doing the calculation for the house subpanel do I leave out the square footage math and treat it like the garage subpanel?

Just in case my rambling isn't making sense this is where I'm coming from: garage sub gets calculated as shown above, house sub gets calculated the same way; neither subpanel area is included in the square footage "general load" math. All remaining living areas (living and bedrooms) get covered in the square footage calculation which might give me something like the following:

garage subpanel = 24.8 amps

house subpanel = 55.6 amps (est, no math done yet)

main = 10.5 amps (837 sq. ft. X 3 watts)/240

giving me a total sum load of 90.9 amps

Does this seem right or is there some seriously flawed thinking on my part? If so please, please tell me where I go off the rails.