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Discussion Starter · #1 · (Edited)
I think I've got this correct but want to make sure.

18 cu inch box
14/2 wire
Single receptacle (standard duplex)

I have incoming power and two outgoing 14/2s (3 wires coming in the box). By my math, I have 2 for the receptacle, 6 conductors and 1 ground for a total of 9 which almost fills the box? Pigtail is ignored.

Is this the right math? With 14GA wire my factor is two, so 7x2=14+2(receptacle)?

Thanks for the help everyone! Love this site!!
 

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2,052 Posts
I think I've got this correct but want to make sure.

18 cu inch box
14/2 wire
Single receptacle (standard duplex)

I have incoming power and two outgoing 14/2s (3 wires coming in the box). By my math, I have 2 for the receptacle, 6 conductors and 1 ground for a total of 9 which almost fills the box? Pigtail is ignored.

Is this the right math? With 14GA wire my factor is two, so 7x2=14+2(receptacle)?

Thanks for the help everyone! Love this site!!
Your receptacle counts as 2 conductors or in this case 4 cu in.
6 Conductors, 1 for ground, 2 for receptacle. #14 = 2 so 9x2=18 cu in
And when using 14/3 for 3-way switches the travelers don't count?
Each traveler count as a conductor. If one cable is 14-3 you will be over filled.
 

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66 Posts
Discussion Starter · #6 ·
Ok ... Makes sense. I was missing the receptacle counting as 2 and therefore 4 cu in.

And my 14/3 comment was actually in reference to another box and just making sure I had the math right.

So for 14G all conductors count for 2 (including travelers), 1 for all ground and 2 for each receptacle or switch, correct? Take that total and multiply by 2 to get the cu inches - correct?
 
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