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 Futurearchitect 01-30-2011 02:19 PM

45" span

I want to span 36' with a 6X6 HSS
there is no roof or floor load on the span. 10' per foot show load
canopy roof will 15 feet below also with a 10' snow load.

the beam is 46' with two 5' sheer supports on both sides

I worried about the beam buckling under its own weight.

Thanks

 Jackofall1 01-30-2011 02:38 PM

Haven't run the calc's but I would say, that a 6 x 6 of unknow thickness wouldn't span 36', there are beams that would able to span 36' with the right cross section.

Given your screen name "future architect" I would think that you are close enough to someone with enough engineering knowledge to size the member you need.

Mark

 Daniel Holzman 01-30-2011 02:41 PM

You need to post a carefully drawn diagram with your comments, I can't figure out what you are talking about. As for the loads, do you mean 10 pounds per square foot of snow load, or have you computed the snow load as 10 pounds per linear foot? And what is a sheer support, are you using nylon stockings to hold up the end of the beam?

As for the beam buckling under its own weight, are you planning to compute buckling load, or are you concerned about bending? Buckling is very complex to compute, bending is easier, but you still need a very carefully drawn diagram, and careful analysis of the actual load on the beam, before you can calculate the factor of safety against buckling, bending, and shear.

 Jackofall1 01-30-2011 02:44 PM

Quote:
 Originally Posted by Daniel Holzman (Post 581078) And what is a sheer support, are you using nylon stockings to hold up the end of the beam?
OMG......LMAROTC:eek::laughing::thumbup:

 Futurearchitect 01-30-2011 03:35 PM

Well I sure know what this place is all about

I new this would fail. I was just testing the site.

Telling all my friends not to use this forum.
tx.

 Steeler99 01-30-2011 03:39 PM

I wouldn't use an HSS, I'd just a WF with plates welded to the sides to make it appear to be an HSS. A general rule of thumb would be take the span and divide it by two, that's the minimum height of the beam that you need. That's for floor loads. But consult with a PE, I wouldn't chance it

 Jackofall1 01-30-2011 03:48 PM

Quote:
 Originally Posted by Futurearchitect (Post 581126) I new this would fail. I was just testing the site. Telling all my friends not to use this forum. tx.
What did you expect, really, there isn't any usable information in your initial question.

Like Daniel said, do up a sketch, post it with a well thought out explanation and then you will get a qualified answer.

Mark

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