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01-26-2012, 11:14 AM   #1
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## Volume of water in pool

Recently i moved into a house with a pool. The size of the pool is;
30ft long x 20 feet wide. the deepest part is 6ft and the shallow part is 3ft. Can someone please help me on how to calculate the volume of water.

01-26-2012, 11:23 AM   #2
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30x20x6=3600 cubic ft
30x20x3=1800 cubic ft
If your pool is half shallow end and half deep end your volume would be 2700 ft^3.

 The Following User Says Thank You to michaelcherr For This Useful Post: florida56 (01-26-2012)
 01-26-2012, 11:25 AM #3 Jack of all - master none     Join Date: Aug 2007 Location: SW Suburbs of Chicago Posts: 1,301 Rewards Points: 686 I think to be more exact, we'd need to know how much of the pool is deep, how much is shallow, and if the shallow end slopes to the deep end, how long is that slope? To add to the above post, 2700 cubic feet is about 20,200 gallons.

01-26-2012, 11:33 AM   #4
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Quote:
 Originally Posted by hyunelan2 I think to be more exact, we'd need to know how much of the pool is deep, how much is shallow, and if the shallow end slopes to the deep end, how long is that slope? To add to the above post, 2700 cubic feet is about 20,200 gallons.
Thanks for your help. What i really wanted to know is how to do the math.

 01-26-2012, 11:41 AM #5 Jack of all - master none     Join Date: Aug 2007 Location: SW Suburbs of Chicago Posts: 1,301 Rewards Points: 686 Oh. Well, like michaelcherr pointed out, you just calculate the volume (LxWxH). If you have only 2 squared off areas (no slope), then you would do like he did in his calculations. If there is a slope between the two areas, you'll need to calculate it out in a couple of parts (The 3' area, the 6' area, and the area above the slope) then add these areas together. Any of these will show a result in cubic feet. 1 cubic foot is equal to about 7.48 gallons of water. So, you then multiply your total cubic feet by 7.48 to get the number of gallons. If you want to be very exact, 1 cuft = 7.48051948 gallons (Google).
01-26-2012, 11:50 AM   #6
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I'll go one step further, here is a diagram.

Assuming the 3' deep and 6' parts are both 10' wide, and the sloped part is also 10' wide, here is what you have.

Calculate up the square foot areas of each of these sections:
6x10 = 60
10x3 = 30
10x3 = 30
10*3/2 = 15 (triangle = base x height / 2)

Add them together: 60+30+30+15 = 135 square feet.

Multiply 135 x 20 (the width of the pool) = 2700 cubic feet - the same as if there was no sloped area in this case (since the deep and shallow parts are equally sized).

2700 cubic feet x 7.48 gallons per foot = 20,196 gallons.
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 The Following 2 Users Say Thank You to hyunelan2 For This Useful Post: burnt03 (01-26-2012), florida56 (01-26-2012)

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