Here's my situation. I have an area that shaped like a "TRIANGLE" that are 24ft. wide by 10ft High. I wanted to find out HOW MUCH it will cost to cedar side it. Asssume that the cost was .60 cents per/ft for a 1/2"x4" bevel cedar siding.
Any idea how I can calculate how many boards and how much will it cost me? Please show me the formula how to do this?
Thanks in advance.
24 x 10 x .5 is your area. (120 SF)
I'd figure you'd need about a 15% waste factor, but I'm no expert.
Figure 140 SF worth of material. How much coverage do you get with the material?
Here's a simple drawing of what I'm looking at doing.
Here's what I figured out...
1440 sq.ft x .60=$864???
I gave you the area in my last post, where do you get 480 from?
Explain your formula a little better if you would.
well, I used formula A+B=C??
Here's my second attempt?????
(24ft x 10ft)=240 sq/ft.
Since the width of the wall is 24ft. wide and it cost .60 cents per/ft. I take 24ft. x .60 cents = $14.40.
Since I have a 10ft. High wall. I need to convert 10ft. into "INCHES" [120"] to determine how many boards I need? 120/4 = 30 baords.
To find out the total cost I take $14.40 x 30= $432????
Is this even correct?
Try it this way. You have 120 SF of area. Call it 140 SF with a healthy waste factor (15%).
Your boards will probably need a 1" lap. This means you basically cover 3" with each row of boards. (1" of each board is "wasted" or hidden", so we pretend that each board is actually 3" high. comprende?)
Instead of trying to figure a triangle, change it to a rectangle or square.
14' wide x 10' high would be 140 SF.
10' = 120"
120" / 3 = 40 rows of siding 14' long to cover your area.
40 rows x 14' = 560 lineal feet of siding.
560 x 0.60 = $336
Or convert your lf cost of .6 to a sf cost. 3" of cover so it'll take 4' to cover a sf..
.6 x 4 = $2.40 / sf
2.40 x 140sf = $336
Just another method of what Kevin K did.
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