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 DIY Chatroom Home Improvement Forum Need help calculating the length for a cut
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02-05-2013, 12:18 PM   #1
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## Need help calculating the length for a cut

Not sure if I'm just slow today or what, but I can't figure this out. Building a work bench onto a wall using 2x4s. Bench comes 21" from the wall and I'm trying to make the angle cuts to go from the outside 2x4 to the wall (basically a triangle). Can anyone tell me how to figure this?

02-05-2013, 12:31 PM   #2
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A squared plus B squared equals C squared according to Mr Pythagorus.

Not sure how far down you want it to go on the wall.

B

 02-05-2013, 12:33 PM #3 "You can do anything"-Mom     Join Date: Oct 2012 Location: Littleton, CO Posts: 724 Rewards Points: 500 Pythagorean theorem (a^2) * (b^2) = c^2 If both legs are 21" then its 441" + 441" = c^2 882" = c^2 c = 29.7"

 02-05-2013, 12:40 PM #4 "You can do anything"-Mom     Join Date: Oct 2012 Location: Littleton, CO Posts: 724 Rewards Points: 500 Also if you make both legs the same say 16" and 16" then you have essentially the diagonal of a square. Length of brace would be length of leg times the square root of 2. Your cuts are easier if the legs are the same. 45 degrees each.
 02-05-2013, 01:34 PM #5 Newbie   Join Date: Apr 2011 Location: Leander, TX Posts: 18 Rewards Points: 10 Got it at 30"! Thanks guys! My geometry really stinks!
02-05-2013, 01:40 PM   #6
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Quote:
 Originally Posted by rkwerchan Got it at 30"! Thanks guys! My geometry really stinks!
No problem. Looks like you are off to a great start. Post some progress and finish pics. I'm sure everyone here would like to see it finished!

02-05-2013, 03:57 PM   #7
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This was just a quickie. Just got divorced and the wife got the house with the big garage and my big workbench. Just needed a place to work on my guns so I threw this together. Also used it as an excuse to buy a new miter saw then realized I have no place to keep it...

Thanks again for the help!

Last edited by rkwerchan; 02-05-2013 at 03:59 PM.

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