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02052013, 12:18 PM  #1 
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Join Date: Apr 2011
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Need help calculating the length for a cut
Not sure if I'm just slow today or what, but I can't figure this out. Building a work bench onto a wall using 2x4s. Bench comes 21" from the wall and I'm trying to make the angle cuts to go from the outside 2x4 to the wall (basically a triangle). Can anyone tell me how to figure this?
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02052013, 12:31 PM  #2 
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Need help calculating the length for a cut
A squared plus B squared equals C squared according to Mr Pythagorus.
Not sure how far down you want it to go on the wall. B Advertisement 
02052013, 12:33 PM  #3 
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Need help calculating the length for a cut
Pythagorean theorem
(a^2) * (b^2) = c^2 If both legs are 21" then its 441" + 441" = c^2 882" = c^2 c = 29.7" 
02052013, 12:40 PM  #4 
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Need help calculating the length for a cut
Also if you make both legs the same say 16" and 16" then you have essentially the diagonal of a square.
Length of brace would be length of leg times the square root of 2. Your cuts are easier if the legs are the same. 45 degrees each. 
02052013, 01:34 PM  #5 
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Need help calculating the length for a cut
Got it at 30"! Thanks guys! My geometry really stinks!

02052013, 01:40 PM  #6 
"You can do anything"Mom
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Need help calculating the length for a cut 
02052013, 03:57 PM  #7 
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Join Date: Apr 2011
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Need help calculating the length for a cut
This was just a quickie. Just got divorced and the wife got the house with the big garage and my big workbench. Just needed a place to work on my guns so I threw this together. Also used it as an excuse to buy a new miter saw then realized I have no place to keep it...
Thanks again for the help! AdvertisementLast edited by rkwerchan; 02052013 at 03:59 PM. 
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