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Old 02-05-2013, 11:18 AM   #1
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Need help calculating the length for a cut


Not sure if I'm just slow today or what, but I can't figure this out. Building a work bench onto a wall using 2x4s. Bench comes 21" from the wall and I'm trying to make the angle cuts to go from the outside 2x4 to the wall (basically a triangle). Can anyone tell me how to figure this?

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Old 02-05-2013, 11:31 AM   #2
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Need help calculating the length for a cut


A squared plus B squared equals C squared according to Mr Pythagorus.

Not sure how far down you want it to go on the wall.

B

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Old 02-05-2013, 11:33 AM   #3
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Need help calculating the length for a cut


Pythagorean theorem

(a^2) * (b^2) = c^2

If both legs are 21" then its

441" + 441" = c^2
882" = c^2
c = 29.7"
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Old 02-05-2013, 11:40 AM   #4
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Need help calculating the length for a cut


Also if you make both legs the same say 16" and 16" then you have essentially the diagonal of a square.

Length of brace would be length of leg times the square root of 2.

Your cuts are easier if the legs are the same. 45 degrees each.
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Old 02-05-2013, 12:34 PM   #5
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Need help calculating the length for a cut


Got it at 30"! Thanks guys! My geometry really stinks!
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Old 02-05-2013, 12:40 PM   #6
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Need help calculating the length for a cut


Quote:
Originally Posted by rkwerchan View Post
Got it at 30"! Thanks guys! My geometry really stinks!
No problem. Looks like you are off to a great start. Post some progress and finish pics. I'm sure everyone here would like to see it finished!
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Old 02-05-2013, 02:57 PM   #7
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Need help calculating the length for a cut


This was just a quickie. Just got divorced and the wife got the house with the big garage and my big workbench. Just needed a place to work on my guns so I threw this together. Also used it as an excuse to buy a new miter saw then realized I have no place to keep it...


Thanks again for the help!


Last edited by rkwerchan; 02-05-2013 at 02:59 PM.
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