How do you determine the calculated load of a 6 Kw electric space heater unit and a 4 kW A/C using the optional method?
I thought when it was reasonable to assume that both of these units would not operate at the same time, that the lower wattage unit could be disregarded in the calculation and that the larger wattage could be used.. But the answer seems to be 4000 watts. I do not understand how they arrived at that answer. This question is from a 2005 NEC quiz.
Post question at wwwmikeholtforums.com. All pros!
|All times are GMT -5. The time now is 05:42 AM.|
vBulletin Security provided by vBSecurity v2.2.2 (Pro) - vBulletin Mods & Addons Copyright © 2016 DragonByte Technologies Ltd.
User Alert System provided by Advanced User Tagging (Pro) - vBulletin Mods & Addons Copyright © 2016 DragonByte Technologies Ltd.